Write the standard equation for the parabola with the given characteristics. vertex:(0,0) directrix:y= 1.
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algebra 2
a quadratic equation can be written in vertex form or in standard form. sometimes one form is more beneficial than the other. identify which form would be more helpful if you needed to do each task listed below and explain why. a. factor the equation. b.

algebra 2
A quadratic equation can be written in vertex form or in standard form. Sometimes one form is more beneficial than the other. Identify which form would be more helpful if you needed to do each task listed below and explain why a. factor the equation b.

algebra
Suppose a parabola has a vertex (4,7) and also passes through the point (3,8) Write the equation of the parabola in vertex form. f(x)=a(xh)^2+k I believe h=4 k=7 Not sure what to do from here.

algebra
Can someone check my answers please and if Im wrong please explain. 1) graph 4x^2+4y^2=64. what are the domain and range? domain;all real numbers range;4

algebra
A few more question Id like for someone to check please. 1) what are the vertex, focus, and directrix of the parabola with the given equation? x^28x28y124=0 vertex (4,5) focus (0,7) directrix y=12 2) write an equation of a circle with given center and

Algebra
Suppose a parabola has an axis of symmetry at x = 2, a minimum height at 6, and passes through the point (0, 10). Write the equation of the parabola in vertex form.

algebra
Suppose a parabola has vertex (4,7) and also passes through the point (3,8), write the equation of the parabola in vertex form.

Math
Write an equation in standard form for each parabola. Vertex (0, 0) and directrix y = 6. y = 1/24x^2?

algebra 2 pls help
A quadratic equation can be written in vertex form or in standard form. Sometimes one form is more beneficial than the other. Identify which form would be more helpful if you needed to do each task as listed below and explain why. a. Factor the equation b.

Math/Algebra
Find the vertex, Focus,and Directrix of the parabola. Graph the equation. y^2=12x

Algebra2
Write an equation of an ellipse in standard form with center at the origin and with the given vertex and covertex vertex at (3,0) and covertex at (0.2)

precalculus
Find the equation of a Parabola with Vertex: (2,4) and directrix: y=7

math
A parabola passes through the point (3, 5) on its way to the vertex at (7, 11). Determine the equation in vertex form that represents this parabola.

Math, please help quickly
Write the equation for a parabola with a focus at (6,0) and a directrix at x=2 ***PLEASE SET AS "x="***

Algebra2
Write an equation of a parabola with a vertex at the origin and a directrix at y=5. my answer is focus 6,0, directrix =6

Geometry
Write an equation of an ellipse in standard form with the center at the origin and with the given characteristics: Vertex (3,0) and covertex (0,2)

Algebra
A parabola can be drawn given a focus of (9, 2)(9,−2) and a directrix of x=3x=3. Write the equation of the parabola in any form.

Geometry
Can someone please help me with these? 1. What are the focus and directrix of the parabola with the equation y=1/12 xsquared 2. what is an equation of a parabola with a vertex at the origin and directrix y=19/4 3. What are the focus and directrix of the

College Algebra
Find the standard form of the equation of the parabola with the given characteristics and vertex at the origin. Passes through the point (5, 1/8); vertical axis. There is no focus of the parabola or equation given, so how am I suppose to solve this

pre cal
What is the center of the conic whose equation is x^2 + 2y^2  6x + 8y = 0 2.Which one of the following equations represents a hyperbola? (5 points) A) 3x^2 + y^2 + 12x  7 = 0 B) 3x^2 + 3y^2 + 12x  7 = 0 C) 3x^2 + y + 12x  7 = 0 D) 3x^2  3y^2 + 12x  7

math
Write the equation for a parabola with a focus at (3,5)(−3,−5) and a directrix at x=7

CAlculuss
Find, in standard form, the equation of : the parabola with focus at (3,5) and directrix at x=1

calculus
write the vertex form equation of each parabola. 1) Vertex:(5,8), Focus:(21/4, 8) 2) Vertex:(6,9), Directrix: x= 47/8 3)Vertex(8,1) y intercept: 17 4) Open left or right, Vertex: (7, 6), passes through:(11,9) 5)Focus(63/8, 7), Directrix: x= 65/8

algebra
6. Find the equation of each parabola described below. a) parabola with vertex (0,0) and the focus (0,7) b) parabola with focus (3,0) and directrix x=3 c) parabola with vertex (3,3) and directrix x=1 d) parabola with focus (2,1) and directrix y=5 e)

MATH
a. Write an equation compared to the equation of the standard parabola that satisfies the description of each parabola. 1. A parabola whose vertex is (0, 3) 2. A parabola whose vertex is (5, 1) 3. A parabola that opens down and is compressed vertically by

Math
Find the vertex, focus, and directrix of the parabola. x^2  2x + 8y + 9 = 0 x^2  2x +1 = 8y + 9+ 1 (x1)^2 = 8(y1.25) vertex:(1,1.25) focus:(1,.75) directrix: y=3.25

Algebra
The directrix of a parabola is y=9 . The focus of the parabola is (2,5) . What is the equation of the parabola? y=−1/8(x−2)^2+7 y=1/8(x−2)^2−7 y=1/8(x−2)^2+7 y=−1/8(x−2)^2−7

Math
Find the vertex, focus and directrix of the parabola. 4x  y^2  2y  33 = 0 y^2+2y+1 = 4x+33+1 (y+1)^2 = 4(x+8.5) vertex:(1,8.5) focus:(2,8.5) Directrix: x=0 Is this correct?

Math
Find the vertex focus directrix and axis of symmetry of each parabola y²–8x–6y–3=0

maths
Given that the equation of the parabola is 5y^2 + 24x = 0. Find (1)The Axis and vertex of the parabola (ii)The focus and the directrix (iii)The distance from the directrix to the focus

College Algebra
Find the standard form of the equation of the parabola with the given characteristics and vertex at the origin. Passes through the point (1, 1/8); vertical axis. There is no focus of the parabola or equation given, so how am I suppose to solve this

Algebra
Find an equation of a parabola with a vertex at the origin and directrix y= 4

precalculus
y=−3x2−4x+1 (a) Write the equation of the parabola in standard form (b) Identify the vertex of the parabola C)Is the vertex a minimum or a maximum? many thanks

Algebra 2
The equation of a parabola is 12y=(x1)^248. Identify the vertex, focus, and directrix of the parabola.

precalculs
Explain what each of the following represents, and how equations (a) and (b) are equivalent. (a) y = a(x  h)2 + k, a ≠ 0 (b) (x  h)2 = 4p(y  k), p ≠ 0 (c) (y  k)2 = 4p(x  h), p ≠ 0 can you check my work and explain how equations (a) and (b) are

math
Find the vertex AND factored form equation for both situations 1) A parabola has vertex (1, 3) and goes through point (2, 5). 2) Write the equation for the parabola with xintercepts (0, 1) and (0, 3) and stretched by a factor 4.

pre cal
write the standard form equation of the parabola with vertex (2,2) that goes through point (1,0) y= a (xb)^2 + c b has to be 2, that gives the shift to the left. y=a( x+2)^2 + c when x=2, y=2, that makes c 2 y=a( x+2)^2 2 finally, put the point

precalculus
.Find the standard form of the equation of the parabola with focus(8,2) and directrix x=4

MATH! Urgent
umm suppose a parabola has a vertex at (0,2) and points (1,1) how would I derive the equation and focus, i've been trying to understand this for so long, I can't get it. Does this parabola have the equation (y2)^2 = x and a focus of 1/4?? Is that

Math
Find the vertex, focus, and directrix of the parabola. x^2  2x + 8y + 9 = 0 x^2  2x +1 = 8y + 9+ 1 (x1)^2 = 8(y1.25) vertex:(1,1.25) focus:(1,.75) directrix: y=3.25 My teacher said that I have sign errors. I do not know where I went wrong.

Algebra
The focus of a parabola is (0,−4) . The directrix of the parabola is the line y=−5 . What is the equation of the parabola? y=−1/4x^2+4 y=1/2x^2−9/2 y=−1/2x^2−9/2 y=1/4x^2−4

MATH PLS HELP
Write the equation of the parabola in vertex form. vertex (1, 3), point (2, 4) f(x)=

math
Find the standard form of the equation of the parabola with the given characteristics. Vertex: (9, 8); directrix: x = 16

Pre Cal
write the equations of the parabola, the directrix, and the axis of symmetry. vertex: (4,2) focus: (4,6) if someone could explain how to do this problem then that would be great! thanks in advance! Formats to help you find the equation for a parabola: (x

precallcuslus
can you check my work and explain the last question because I do not uderstand. Explain what each of the following represents, and how y = a(x  h)2 + k, a ≠ 0 and (x  h)2 = 4p(y  k), p ≠ 0 are equivalent. The equation (x  h)2 = 4p(y  k), p ≠ 0

Math
Identify the equation of a parabola whose focus is at (5,1) and whose directrix is x=3. vertex=(5,1) p=6 4p=24 (x5)=(24)(y+1)^2 I got it wrong

Algebra 1 parabola's
I have a graph with a parabola on it and asked to write the function for f(x) in standard form. I know that standard is y=ax^2+bx+c obviously, since the points are on the graph we know x and y so a,b and c need to be found. The vertex is on (4,4) the

math
write an equation for the parabola with focus (1,3) and vetex (0,3) See the paragraph Analytic Geometry Equations. You will have a choice of equations, you did not state whether the axis of symettry was parallel to x or y axis.

Math
Write the equation of a parabola, in standard form, that goes through these points: (0, 3) (1, 4) (1, 6) ax^2 + bx + c = y a * 0^2+b*0+c = 3 a*1^2+b+1+c = 4 a*(1)^2+b(1)+c = 6 c = 3 a + b + c = 4 a – b + c = 6 a + b + 3 = 4 a – b + 3 = 6 Graph

algebra II
Can you please help me with the these problems. 8.Write an equation in standard form of the parabola that has the same shape as the graph of f(x) = 11x^2, but which has its vertex at (2, 9). 10. Use the vertex and intercepts to sketch the graph of the

math
A parabola has the equation y = 4(x3)^27 Choose 2 true statements: A) The parabola has a minimum value B) The parabola has a maximum value C) The parabola does not cross the yaxis D) The parabola does not cross the xaxis E) The vertex of the parabola

algebra 2
Find the vertex, focus, axis, directrix and latus rectum of the parabola x^2+ y = 6x  14

math
Write the standard equation for the parabola with the given characteristics. vertex:(0,0) directrix:y= 1.

Algebra II
Write an equation for the parabola with focus (1,3) and vertex (0,3). I cannot find any example in my book that works a problem with the vertex, all of the examples that I have to go by give only the focus and directrix. Thanks.

Alg II/Trig
A parabola has a vertex at (0,0); a horizontal axis; and the point (12,6) is on the parabola. Write the equation of the parabola in standard form.

Math
determine vertex, focus and directrix of parabola. then graph the parabola. first equation: y^2 2x8=0 second equation: y^2 4y 12x= 8 please show your work!

Math
determine vertex, focus and directrix of parabola. then graph the parabola. second equation: y^2 4y 12x= 8

math
determine vertex, focus and directrix of parabola. then graph the parabola. first equation: y^2 2x8=0 second equation: y^2 4y 12x= 8

Algebra
I am supposed to write the standard equation of the parabola with the directrix x=1, and the vertex 6,2. I got y6=1/4p(x2)^2. Is this correct? I am supposed to graph y+3=1/12(x1)^2. I tried to find p, and I got 36. I don't think this could be correct,

Math
determine vertex, focus and directrix of parabola. then graph the parabola. second equation: y^2 4y 12x= 8 Please help me this is do 2day bc i forget to turn it in to my teacher

math
Write the equation in standard form, given the following information. vertex(2,4), directrix y=1

Algebra
Find an equation of a parabola with a vertex at the origin and directrix y =–4

algebra 2
Directions: The focus and directrix of a parabola are given. Write an equation for each parabola. (2,4) y = 6 May you explain the procedures on how to solve this equation? Please be detailed on each step.

PreCalc
for the conic y=5x^240x+78 find an equation in standard form and its vertex, focus, and directrix

algebra
How would one write the equation of a parabola whose directrix is y=6 and location of the focus is (3,2)

Algebra 2
Point (6,2) lies on a parabola that has its vertex at (0,1). Write the equation of the parabola. Indicate whether the graph opens up or down.

algebra
A parabola has xintercepts at 3 and 7, a yintercept at 21, and (5,4) for its vertex. Write the parabola’s equation

Math 11
write the equation in vertex form, of a parabola with vertex (5, 1) and that passes through the point (6, 8)

Vertex, Focus, & Directrix of Parabolas
Find the Vertex, Focus, and Directrix of the parabola: x^2 12x48y+276=0 Thank you so much

Math Grade 10
41. Compare the parabola defined by each equation with the standard parabola defined by the equation y = x². Describe the corresponding transformations, and include the position of the vertex and the equation of the axis of symmetry. y = 3x²  8 (4

Math Help
With the given information below, write the standard form equation for the parabola. 1.) Vertex: (1,2) Focus(1,0) 2.) Vertex: (2,1) Directrix x=1

MATH
Write the equation of a parabola with a vertex at (5, 2) and a directrix y = 1.

Honors Algebra 2
Write an equation in standard form of the parabola that has the characteristics below. Vertex at (1,8); passing through the point (3,12) So I started the problem and now I'm stuck as of what to do next. Y=a(xh)+k 12=a(31)^28 12=a(2)^28 12=4a8 4=4a

Algebra
Can you please help me with the below question: The vertex of a parabola is located at (12, 1). The parabola also passes through the point (10, 5). Write the equation of this parabola in both vertex form and standard form. Vertex form: Standard form:

Precal
Sketech the graph of the equation y^2+4y+2x+10=0. Identify the vertex, the focus and the equation for the directrix. Use the completing the square to put the equation into standard form as your first step. This is what I did. y^2 + 4y = 2x10 y^2 + 4y + 4

Math
Write the standard form of the equation of the parabola whose directrix is x=1 and whose focus is at (5,2)? a) (y+2)^2 = 12(x+2) b) y2 = 12(x+2) c) x+2 = 1/12(y+2)^2 d) x2 = 1/12(y+2)^2 I get A and D? confused!

PreCalculas check
Write the equation of the parabola 1.Vertex(2,5) Focus(2,3) 2.Directrix=x=3/4 Focus(5/4,3) For 1. i got(x2)^2=32(y5)^2 For 2. i got y=8x^220x61/60

PreCalculas
Write the equation of the parabola 1.Vertex(2,5) Focus(2,3) 2.Directrix=x=3/4 Focus(5/4,3) For 1. i got(x2)^2=32(y5)^2 For 2. i got y=8x^220x61/60

Pre Cal Check
focus: (0,p) vertex: if not given, then it is assumed (0,0) Directrix: k+p or kp, i'm not sure I think these are the general equations for the focus, vertex, and directrix of a parabola, but i'm not sure. could someone please check this? thanks.

mathematics
Find the equation of the parabola with the vertex at the origin and directrix y =5

algebra
1)What is the distance between the museum and sailing club.I cant post the graph or anything but I have my numbers right its 53 but I used the distance formula so its either 53 units or the square root of 53 units. 2)Write the equation of the parabola y=

Algebra
Can someone tell me if I am right? I need to find the equation of a parabola. I am not sure if this is the correct way or if I have the correct answer. Vertex at origin, focus is at (0,3) Equation of parabola vertex (0,0) focus (0,3) focus (h,k+p) (0,0+3)

Algebra
Write the standard form of the equation of the parabola whose vertex is 1,2 and passes through the point 0,0. The answer according to my book is 0=a(01)^2+2. But which 0 in the equation is the first 0 fromn (0,0) and which one is the second? Thanks!

math
A parabola has the equation y = 4(x3)^27 Choose 2 true statements: A) The parabola has a minimum value B) The parabola has a maximum value C) The parabola does not cross the yaxis D) The parabola does not cross the xaxis E) The vertex of the parabola

Algebra2
A quadratic equation can be written in vertex form or in standard form. Sometimes one form is more beneficial than the other. Identify which form would be more helpful if you needed to do each task listed below and explain why. a factor the equation b

Precalc
i need help with this equation anything help will be greatly appreciated find the standard equation of a parabola with a focus (2,0) directrix x=3

ALGEBRA 1
Please check for me.Without drawing the graph of the given equation determine (a)how many xintercepts the parabola has (b)whether it vertex lies above, below or on the axis. 1. y=x^25x+6 I use the determinant sqrt b^2 4ac (5)^24(1)(6))=1 There are two

Math
Using the following information for the Vertex and Directrix, write the standard form equation for the parabola with what is given below. Vertex: (2,1) Directrix: x=1

pre cal
find the standard form of the equation of a parabola with the vertex (0,0) and the directrix y=6 find the standard form of the equation of the ellipse with center (0,0) and foci at (+ 4square root 3, 0) and verticies (+8,0)

pre calculus
Find the equation of a Parabola with Vertex: (2,1) and directrix: x= 2

Advanced Math
Identify the equation of a parabola whose focus is at (5,1) and whose directrix is x=3. vertex=(5,1) p=6 4p=24 (x5)=(24)(y+1)^2 I got it wrong

math
the points (9,0) and (19,0) lie on parabola. a.) determine an equation for its axis of symmetry: X=5 b.) the ycoordinate of the vertex is 28. determine an equation for the parabola in factored form. c.)write your equation in part b) in standard form.

algebra problem
I need to find the equation of a parabola. I am not sure if this is the correct way or if I have the correct answer. Vertex at origin, focus is at (0,3) Equation of parabola vertex (0,0) focus (0,3) focus (h,k+p) (0,0+3) y=03 directrix y=3 a=(1/4)(p)

precal
what is the vertex and directrix of the parabola y=1/2x^2 + 10  46

math
hi i was wondering how would you find the equation of a parabola with it's vertex at 2,0, and with no directrix or focus given. the parobala opens toward the left. the two choices in my multiple choice answer sheet that sound the most logical would be

ALGEBRA 1
Please check for me.Without drawing the graph of the given equation determine (a)how many xintercepts the parabola has (b)whether it vertex lies above, below or on the axis. 1. y=x^25x+6 I use the determinant sqrt b^2 4ac (5)^24(1)(6))=1 There are two

Math
Write an equation for the parabola with focus (0, 0) and directrix y = 1. I got x^2  2y + 1, but how do I get it in the form y  k = 1/4p(x  h)^2?

precalculus
can you check my work I really do not understand. Find the standard form of the equation of the parabola with focus(8,2) and directrix x=4. answer= (y+2)^2=16(x12/8)

maths
In case of parabola y= x^22x3 Find: a)Vertex: b)Axis: c)Focus: d)Directrix: e)Latus Rectum:

PreCalculus
How do I solve these equations? I need to create an equation given the characteristics? I have to be able to graph a parabola but first I need help solving this. 1.Focus (1.5,1); opens right; directrix x=0.5 2.Focus (1,4);opens down; contains (3,1)